The Forward Measure¶
The \(T\)-forward measure is a probability measure that uses the zero-coupon bond \(P(t,T)\) as numéraire. It is particularly useful for pricing interest rate derivatives where the payoff occurs at a specific future date \(T\).
The central advantage of the forward measure is that it removes the randomness of discounting: pricing reduces to \(P(t,T)\,\mathbb{E}^{\mathbb{Q}^T}[\Phi_T]\) with a deterministic prefactor, avoiding the correlation between stochastic discount factor and payoff that complicates the risk-neutral valuation formula.
Definition¶
The forward measure is the numéraire framework applied to the \(T\)-maturity zero-coupon bond \(P(t,T)\) (with \(P(T,T) = 1\) and \(P(t,T) > 0\)).
By the change-of-numéraire formula, the \(T\)-forward measure \(\mathbb{Q}^T\) has Radon–Nikodym derivative:
where \(B_t = e^{\int_0^t r_s\,ds}\) is the money market account and \(\mathbb{Q}\) is the standard risk-neutral measure.
Key Properties¶
Recall (see § The Fundamental Theorem for Numéraires): for any traded asset \(S_t\), the bond-deflated price \(S_t / P(t,T)\) is a \(\mathbb{Q}^T\)-martingale. Specialised to \(S_t\), this is the forward price
since \(F(T,T) = S_T\). For a claim with payoff \(\Phi_T\) at time \(T\):
No explicit discounting is required — the bond price handles it.
Comparison: Risk-Neutral vs Forward Measure¶
| Aspect | Risk-Neutral \(\mathbb{Q}\) | Forward \(\mathbb{Q}^T\) |
|---|---|---|
| Numéraire | Money market \(B_t\) | Bond \(P(t,T)\) |
| Martingale | \(S_t/B_t\) | \(S_t/P(t,T)\) |
| Pricing | \(V_t = \mathbb{E}^{\mathbb{Q}}[e^{-\int_t^T r_s\,ds}\Phi_T]\) | \(V_t = P(t,T)\mathbb{E}^{\mathbb{Q}^T}[\Phi_T]\) |
| Discount | Stochastic | Deterministic factor \(P(t,T)\) |
Dynamics Under the Forward Measure¶
Brownian Motion Change¶
Under \(\mathbb{Q}\): \(W_t^{\mathbb{Q}}\) is Brownian motion.
The change of numéraire from \(B_t\) to \(P(t,T)\) shifts the Brownian motion by the bond volatility \(\sigma_P(t,T)\):
is Brownian motion, where \(\sigma_P(t,T)\) is defined through the bond dynamics:
Asset Dynamics¶
If under \(\mathbb{Q}\) the asset and bond are driven by (possibly correlated) diffusions with volatilities \(\sigma_S\) and \(\sigma_P(t,T)\) and instantaneous correlation \(\rho_{S,P}\), then the asset dynamics change from
to
The drift acquires the extra term \(\sigma_S\,\sigma_P(t,T)\,\rho_{S,P}\), which is precisely the instantaneous covariance between the asset return \(dS/S\) and the bond return \(dP/P\). This covariance correction arises because the Girsanov shift from \(\mathbb{Q}\) to \(\mathbb{Q}^T\) is driven by the bond volatility \(\sigma_P(t,T)\): the change of numéraire tilts probabilities in proportion to the bond's own diffusion, and every correlated diffusion picks up a corresponding drift adjustment.
Example: LIBOR Forward Rate¶
Definition¶
The forward LIBOR rate \(L(t;T,T+\delta)\) for period \([T, T+\delta]\) is defined by:
Under the (T+δ)-Forward Measure¶
The forward LIBOR rate is a \(\mathbb{Q}^{T+\delta}\)-martingale:
At time \(T\), the spot LIBOR fixes: \(L(T;T,T+\delta) = L_T\).
Caplet Pricing¶
A caplet with strike \(K\) pays \(\delta(L_T - K)^+\) at time \(T+\delta\).
Under \(\mathbb{Q}^{T+\delta}\):
If \(L(t;T,T+\delta)\) is log-normal under \(\mathbb{Q}^{T+\delta}\) with volatility \(\sigma_L\):
This is Black's formula for caplets.
Example: Forward Contract¶
Setup¶
Forward contract to buy asset \(S\) at time \(T\) for price \(K\).
Payoff at \(T\): \(\Phi_T = S_T - K\).
Under Risk-Neutral Measure¶
Requires knowing the joint distribution of \(r\) and \(S\).
Under Forward Measure¶
Since \(F(t,T)\) is a \(\mathbb{Q}^T\)-martingale: \(\mathbb{E}^{\mathbb{Q}^T}[S_T] = F(t,T)\).
Much simpler! No need to model \(r\) and \(S\) jointly.
The Forward Measure in Vasicek Model¶
Recall (see § Vasicek Example): under \(\mathbb{Q}\), \(dr_t = \kappa(\bar r - r_t)\,dt + \sigma_r\,dW_t^{\mathbb{Q}}\) and the bond price is \(P(t,T)=A(t,T)e^{-B(t,T)r_t}\) with \(B(t,T)=(1-e^{-\kappa(T-t)})/\kappa\). The bond volatility is \(\sigma_P(t,T) = -B(t,T)\sigma_r\), and substituting into the Girsanov shift \(W^{\mathbb{Q}^T}_t = W^{\mathbb{Q}}_t - \int_0^t \sigma_P(s,T)\,ds\) gives the short-rate dynamics under the \(T\)-forward measure:
The extra drift \(-\sigma_r^2 B(t,T)\) is the convexity adjustment.
Multiple Forward Measures¶
For different maturities \(T_1 < T_2\):
Each maturity has its own forward measure.
The Tower of Measures¶
All are equivalent measures connected by Radon–Nikodym derivatives.
When to Use the Forward Measure¶
| Problem | Use Forward Measure When |
|---|---|
| European options | Payoff at single date \(T\) |
| Caps/Floors | Separate caplet for each period |
| Bond options | Option on \(P(T,S)\) at time \(T\) |
| Forward starting options | Payoff depends on forward price |
Avoid forward measure for:
- Path-dependent options (use \(\mathbb{Q}\))
- American options (early exercise)
- Options with multiple payment dates (use swap measure)
Summary¶
| Property | Statement |
|---|---|
| Numéraire | Zero-coupon bond \(P(t,T)\) |
| Martingale | Forward price \(F(t,T) = S_t/P(t,T)\) |
| Advantage | Eliminates stochastic discounting |
| Use case | Interest rate derivatives |
All forward measures \(\mathbb{Q}^{T_1}, \mathbb{Q}^{T_2}, \ldots\) and the risk-neutral measure \(\mathbb{Q}\) are equivalent --- they agree on which events are possible and differ only in how they weight outcomes. The choice among them is a matter of computational convenience, not of economic content.
The forward measure transforms the problem of stochastic discounting into a problem of computing a simple expectation, making it indispensable for interest rate modeling.
Exercises¶
Exercise 1. Write the Radon–Nikodym derivative \(d\mathbb{Q}^T / d\mathbb{Q}|_{\mathcal{F}_t}\) in terms of \(P(t,T)\), \(P(0,T)\), and \(B_t\). Verify that at \(t = T\), this expression simplifies to \(e^{-\int_0^T r_s\,ds} / P(0,T)\). Explain why \(\mathbb{E}^{\mathbb{Q}}[d\mathbb{Q}^T / d\mathbb{Q}|_{\mathcal{F}_T}] = 1\).
Solution to Exercise 1
By definition:
At \(t = T\): \(P(T,T) = 1\) (the bond pays 1 at maturity) and \(B_T = e^{\int_0^T r_s\,ds}\). Substituting:
To verify \(\mathbb{E}^{\mathbb{Q}}[d\mathbb{Q}^T/d\mathbb{Q}|_{\mathcal{F}_T}] = 1\): Under \(\mathbb{Q}\), the discounted bond price \(P(t,T)/B_t\) is a martingale. Therefore:
since \(B_0 = 1\). Hence:
This confirms the Radon–Nikodym derivative is properly normalized.
Exercise 2. A forward contract on a stock \(S\) for delivery at \(T\) has payoff \(S_T - K\) at maturity. Using the forward measure, show that the value at time \(t\) is \(V_t = P(t,T)(F(t,T) - K)\) where \(F(t,T) = S_t / P(t,T)\). Determine the forward price \(K^*\) that makes the contract initially worth zero.
Solution to Exercise 2
The forward contract pays \(\Phi_T = S_T - K\) at time \(T\). Under the \(T\)-forward measure:
Since the forward price \(F(t,T) = S_t/P(t,T)\) is a \(\mathbb{Q}^T\)-martingale:
(using \(F(T,T) = S_T/P(T,T) = S_T\)). Therefore:
The forward price \(K^*\) that makes the contract initially worth zero satisfies \(V_0 = 0\):
Exercise 3. In the Vasicek model with \(\kappa = 0.3\), \(\bar{r} = 0.05\), \(\sigma_r = 0.02\), and \(B(t,T) = (1 - e^{-\kappa(T-t)})/\kappa\), compute the bond volatility \(\sigma_P(t,T) = -B(t,T)\sigma_r\) for \(T - t = 5\). Write the drift adjustment for the short rate under \(\mathbb{Q}^T\).
Solution to Exercise 3
With \(\kappa = 0.3\), \(\sigma_r = 0.02\), and \(T - t = 5\):
The bond volatility is:
Under \(\mathbb{Q}^T\), the Brownian motion is \(W_t^{\mathbb{Q}^T} = W_t^{\mathbb{Q}} - \int_0^t \sigma_P(s,T)\,ds\), and the short rate dynamics become:
The drift adjustment is \(-\sigma_r^2 B(t,T) = -(0.02)^2 \cdot 2.58957 = -0.001036\) (evaluated at \(T - t = 5\)). This term shifts the short rate drift downward, reflecting the convexity adjustment arising from the correlation between the bond price and the short rate.
Exercise 4. A caplet with strike \(K = 0.05\) on the LIBOR rate \(L(T; T, T+\delta)\) with \(\delta = 0.25\) pays \(\delta(L_T - K)^+\) at \(T + \delta\). If \(L(0; T, T+\delta) = 0.048\) and the forward LIBOR volatility is \(\sigma_L = 0.20\), use Black's formula to price the caplet under \(\mathbb{Q}^{T+\delta}\). Assume \(P(0, T+\delta) = 0.92\).
Solution to Exercise 4
Given: \(K = 0.05\), \(\delta = 0.25\), \(L_0 = L(0;T,T+\delta) = 0.048\), \(\sigma_L = 0.20\), \(P(0,T+\delta) = 0.92\), and maturity \(T\) (we need \(T\) to compute \(d_1, d_2\); we take \(T = 1\) as a typical assumption).
Under Black's formula for the caplet:
where
From normal distribution tables: \(\Phi(-0.1041) \approx 0.4585\) and \(\Phi(-0.3041) \approx 0.3806\).
The caplet price is approximately \(0.0686\%\) of notional, or about \(6.86\) basis points.
Exercise 5. Explain why the forward price \(F(t,T) = S_t / P(t,T)\) is a \(\mathbb{Q}^T\)-martingale but not a \(\mathbb{Q}\)-martingale in general. What is the drift of \(F(t,T)\) under the standard risk-neutral measure \(\mathbb{Q}\)?
Solution to Exercise 5
Under \(\mathbb{Q}\), the discounted price \(S_t/B_t\) is a martingale, where \(B_t = e^{\int_0^t r_s\,ds}\). The forward price is \(F(t,T) = S_t/P(t,T)\). Writing \(F(t,T) = (S_t/B_t) \cdot (B_t/P(t,T))\), note that \(S_t/B_t\) is a \(\mathbb{Q}\)-martingale but \(B_t/P(t,T)\) is a stochastic process (not constant), so their product \(F(t,T)\) is generally not a \(\mathbb{Q}\)-martingale.
To find the drift of \(F\) under \(\mathbb{Q}\), apply Itô's formula to \(F = S/P\). Under \(\mathbb{Q}\):
By the quotient rule (Itô):
The drift \(\sigma_P(\sigma_P - \sigma_S)\) is generally nonzero, confirming \(F\) is not a \(\mathbb{Q}\)-martingale. Under \(\mathbb{Q}^T\), this drift vanishes by construction (the Girsanov shift absorbs it), making \(F\) a \(\mathbb{Q}^T\)-martingale.
Exercise 6. For two different maturities \(T_1 < T_2\), write the Radon–Nikodym derivative \(d\mathbb{Q}^{T_2}/d\mathbb{Q}^{T_1}|_{\mathcal{F}_t}\) and explain why the measures \(\mathbb{Q}^{T_1}\) and \(\mathbb{Q}^{T_2}\) differ. In which financial applications does the choice between these measures matter?
Solution to Exercise 6
The Radon–Nikodym derivative between the two forward measures is:
The measures differ because they use different bonds as numéraires, leading to different probability tilts. Under \(\mathbb{Q}^{T_1}\), the forward price \(S_t/P(t,T_1)\) is a martingale, while under \(\mathbb{Q}^{T_2}\), \(S_t/P(t,T_2)\) is a martingale. The Girsanov kernel connecting them involves the volatility difference \(\sigma_P(t,T_2) - \sigma_P(t,T_1)\).
The choice between these measures matters in applications such as:
- Interest rate caps: Each caplet with reset at \(T_i\) is priced under \(\mathbb{Q}^{T_{i+1}}\), so different caplets in the same cap use different forward measures.
- LIBOR Market Models (BGM): Forward LIBOR rates for different tenors are martingales under different forward measures, requiring careful measure changes when computing joint distributions.
- Convexity adjustments: When a rate observed under one measure must be priced under another (e.g., CMS rates), the measure change introduces a convexity correction.
Exercise 7. Recall (see § Numéraire, Example: Exchange Option) that Margrabe's formula uses \(S^2\) as numéraire. In contrast, when the payoff \((S_T - K)^+\) on a single asset is dated at \(T\), the \(T\)-forward measure is preferred over the money-market numéraire. State the precise advantage of \(\mathbb{Q}^T\) over \(\mathbb{Q}\) when interest rates are stochastic and explain why this advantage disappears when \(r\) is constant.
Solution to Exercise 7
Under \(\mathbb{Q}\), the pricing formula
requires the joint distribution of the stochastic discount factor \(e^{-\int_t^T r_s\,ds}\) and the payoff \(\Phi_T\) — the two are generally correlated when \(r\) is stochastic, so the discount cannot be pulled out of the expectation.
Under \(\mathbb{Q}^T\), the discount factor is replaced by the deterministic prefactor \(P(t,T)\):
Stochastic discounting becomes a single market-observable number, and only the \(\mathbb{Q}^T\)-distribution of \(\Phi_T\) is needed.
When \(r\) is constant, \(e^{-r(T-t)}\) is deterministic and factors out of the \(\mathbb{Q}\)-expectation; meanwhile \(P(t,T) = e^{-r(T-t)}\) as well, and \(\mathbb{Q}^T \equiv \mathbb{Q}\) since the Radon–Nikodym derivative \(e^{-rT}/P(0,T) = 1\). The two formulas coincide and the advantage vanishes.