Construction of the Risk-Neutral Measure¶
This page carries out Level 1 of the FTAP Ladder: construct a probability measure under which discounted asset prices are driftless — that is, martingales.
Construction roadmap
- Discount: form the discounted price \(\tilde{S}_t = S_t / B_t\).
- Identify the obstruction: the drift \((\mu_t - r_t)\) prevents \(\tilde{S}_t\) from being a martingale.
- Define the Girsanov kernel: set \(\theta_t = (\mu_t - r_t)/\sigma_t\).
- Apply Girsanov’s theorem: the tilted measure \(\mathbb{Q}\) makes \(\tilde{S}_t\) a martingale.
Market Model¶
Consider a financial market consisting of:
- a risk-free asset \(B_t\),
- a risky asset \(S_t\).
Under the physical measure \(\mathbb{P}\), assume
where \(\mu_t\), \(\sigma_t\), and \(r_t\) are adapted processes.
Discounted Asset Price¶
Define the discounted price process
Applying Itô’s formula,
The presence of the drift term \((\mu_t - r_t)\) prevents \(\tilde{S}_t\) from being a martingale under \(\mathbb{P}\).
Measure Change¶
Define the market price of risk
Recall (see § The Stochastic Exponential): the density process
is a \(\mathbb{P}\)-local martingale. Recall (see § Novikov and Kazamaki Conditions): the sufficient condition
promotes \(Z_t\) to a true martingale, so \(d\mathbb{Q}/d\mathbb{P}|_{\mathcal{F}_t} = Z_t\) defines an equivalent probability measure \(\mathbb{Q}\).
Risk-Neutral Dynamics¶
Recall (see § Girsanov's Theorem and § Drift Adjustment): under \(\mathbb{Q}\),
is a Brownian motion, and substituting \(dW_t^{\mathbb{P}} = dW_t^{\mathbb{Q}} - \theta_t\,dt\) into the discounted-price SDE eliminates the drift \((\mu_t - r_t)\):
so \(\tilde{S}_t\) is a \(\mathbb{Q}\)-martingale.
Definition¶
A risk-neutral measure is a probability measure \(\mathbb{Q}\) equivalent to \(\mathbb{P}\) under which all discounted traded asset prices are martingales.
Exercises¶
Exercise 1. A stock has physical dynamics \(dS_t = 0.10\,S_t\,dt + 0.25\,S_t\,dW_t^{\mathbb{P}}\) with risk-free rate \(r = 0.04\). Compute the market price of risk \(\theta\), write the Radon–Nikodym derivative \(Z_T\), and derive the discounted price dynamics under \(\mathbb{Q}\). Verify that the discounted price is a \(\mathbb{Q}\)-martingale.
Solution to Exercise 1
Given \(\mu = 0.10\), \(\sigma = 0.25\), and \(r = 0.04\), the market price of risk is
The Radon–Nikodym derivative at time \(T\) is
Under \(\mathbb{Q}\), the process \(W_t^{\mathbb{Q}} = W_t^{\mathbb{P}} + \theta t = W_t^{\mathbb{P}} + 0.24\,t\) is a Brownian motion. Substituting \(dW_t^{\mathbb{P}} = dW_t^{\mathbb{Q}} - 0.24\,dt\) into the stock dynamics:
The discounted price \(\tilde{S}_t = e^{-0.04\,t}S_t\) satisfies
Since the drift vanishes, \(\tilde{S}_t\) is a \(\mathbb{Q}\)-martingale.
Exercise 2. Starting from the discounted price \(\tilde{S}_t = S_t / B_t\) and its dynamics \(d\tilde{S}_t = (\mu_t - r_t)\tilde{S}_t\,dt + \sigma_t\tilde{S}_t\,dW_t^{\mathbb{P}}\), show that choosing \(\theta_t = (\mu_t - r_t)/\sigma_t\) and defining \(W_t^{\mathbb{Q}} = W_t^{\mathbb{P}} + \int_0^t \theta_s\,ds\) eliminates the drift term in the \(\tilde{S}_t\) dynamics. Why is this drift removal equivalent to the martingale property?
Solution to Exercise 2
Starting from the discounted price dynamics
we define \(\theta_t = (\mu_t - r_t)/\sigma_t\) and \(W_t^{\mathbb{Q}} = W_t^{\mathbb{P}} + \int_0^t \theta_s\,ds\). Then \(dW_t^{\mathbb{P}} = dW_t^{\mathbb{Q}} - \theta_t\,dt\), and substituting:
Since \(\sigma_t\theta_t = \mu_t - r_t\), the drift terms cancel exactly:
The drift removal is equivalent to the martingale property because a continuous local martingale of the form \(dX_t = \sigma_t X_t\,dW_t\) has zero drift, meaning \(\mathbb{E}^{\mathbb{Q}}[\tilde{S}_t \mid \mathcal{F}_s] = \tilde{S}_s\) for \(s \le t\) (assuming appropriate integrability). A process is a martingale if and only if it has zero drift in its semimartingale decomposition, so eliminating the drift is precisely what makes \(\tilde{S}_t\) a \(\mathbb{Q}\)-martingale.
Exercise 3. Explain why the risk-neutral measure \(\mathbb{Q}\) must be equivalent to \(\mathbb{P}\) (i.e., both measures agree on which events have probability zero). What would go wrong financially if \(\mathbb{Q}\) assigned positive probability to an event that is impossible under \(\mathbb{P}\)?
Solution to Exercise 3
The risk-neutral measure \(\mathbb{Q}\) must be equivalent to \(\mathbb{P}\), meaning they agree on which events have probability zero. This equivalence is essential for two reasons:
If \(\mathbb{Q}(A) > 0\) for some event \(A\) with \(\mathbb{P}(A) = 0\): Then \(\mathbb{Q}\) assigns positive probability to a physically impossible event. This means derivative prices under \(\mathbb{Q}\) could depend on payoffs in scenarios that can never occur, leading to economically nonsensical prices. One could construct "arbitrage" by selling claims that pay in impossible states, collecting premium for risk that can never materialize.
If \(\mathbb{Q}(A) = 0\) for some event \(A\) with \(\mathbb{P}(A) > 0\): Then there exists a physically possible event whose payoff is completely ignored in pricing. An agent could buy a claim that pays in state \(A\) for zero cost (since \(\mathbb{Q}\) gives it zero weight) but receives a positive payoff with positive physical probability, creating an arbitrage opportunity.
Equivalence ensures a one-to-one correspondence between possible and priced events, which is exactly the no-arbitrage condition.
Exercise 4. For time-varying coefficients \(\mu_t\), \(\sigma_t\), and \(r_t\), the market price of risk \(\theta_t = (\mu_t - r_t)/\sigma_t\) is a stochastic process. State the Novikov condition that ensures \(Z_t\) is a true martingale and \(\mathbb{Q}\) is well-defined. Give an example where the condition fails.
Solution to Exercise 4
The Novikov condition states that \(Z_t\) is a true martingale (and hence \(\mathbb{Q}\) is well-defined) if
This is a sufficient condition ensuring that the stochastic exponential \(Z_t = \exp\!\left(-\int_0^t \theta_s\,dW_s^{\mathbb{P}} - \frac{1}{2}\int_0^t \theta_s^2\,ds\right)\) is a uniformly integrable martingale, not merely a local martingale.
Example where Novikov fails: Consider \(\sigma_t = \sigma\) constant and \(\mu_t - r_t = \sigma / \sqrt{T - t}\) for \(t < T\). Then \(\theta_t = 1/\sqrt{T-t}\) and
The integral diverges, so the Novikov condition fails. In this case, \(Z_t\) may fail to be a true martingale, and a well-defined equivalent measure \(\mathbb{Q}\) may not exist.
Exercise 5. Consider a market with two risky assets and one Brownian motion. Write the system of equations that \(\theta\) must satisfy for both discounted prices to be \(\mathbb{Q}\)-martingales. Under what condition on \(\mu_1, \mu_2, \sigma_1, \sigma_2, r\) is the system consistent (i.e., no arbitrage)?
Solution to Exercise 5
With two risky assets \(S^1, S^2\) and one Brownian motion \(W_t\), the dynamics are
For both discounted prices to be \(\mathbb{Q}\)-martingales, we need a single \(\theta\) satisfying
From the first equation, \(\theta = (\mu_1 - r)/\sigma_1\). Substituting into the second:
This simplifies to the no-arbitrage consistency condition:
Both assets must have the same Sharpe ratio. If this condition is violated, say \((\mu_1 - r)/\sigma_1 > (\mu_2 - r)/\sigma_2\), then no risk-neutral measure exists, and an arbitrage strategy can be constructed: go long asset 1 and short asset 2 in proportions that eliminate the Brownian motion exposure while retaining a positive drift.
Exercise 6. A student claims: "The risk-neutral measure is the probability measure that investors actually use to form expectations." Explain why this is incorrect and describe the correct interpretation of \(\mathbb{Q}\).
Solution to Exercise 6
The risk-neutral measure \(\mathbb{Q}\) is not the probability measure investors use to form expectations. Under the physical measure \(\mathbb{P}\), investors form beliefs about actual probabilities of future events and demand compensation (risk premia) for bearing risk.
The correct interpretation: \(\mathbb{Q}\) is an artificial probability measure constructed so that discounted asset prices are martingales. Under \(\mathbb{Q}\), all assets earn the risk-free rate in expectation — risk premia have been absorbed into the probability weighting. The measure \(\mathbb{Q}\) encodes both the physical probabilities and the market prices of risk into a single object.
Pricing under \(\mathbb{Q}\) is a mathematical convenience, not a statement about investor beliefs. The formula \(V_t = \mathbb{E}^{\mathbb{Q}}[e^{-\int_t^T r_s\,ds}\Phi_T \mid \mathcal{F}_t]\) gives the no-arbitrage price, which reflects both the probability of outcomes (from \(\mathbb{P}\)) and the risk adjustment (from \(\theta\)), combined into the tilted measure \(\mathbb{Q}\). In markets with risk-averse investors, \(\mathbb{Q}\) typically overweights adverse outcomes relative to \(\mathbb{P}\).
Exercise 7. Suppose the risk-free rate is stochastic: \(dr_t = \alpha(r_t)\,dt + \beta(r_t)\,dW_t^{\mathbb{P}}\), and the same Brownian motion drives the stock. Write the discounted stock price dynamics and determine \(\theta_t\). Explain why this market is complete (one Brownian motion, one traded asset besides the bond).
Solution to Exercise 7
With \(dr_t = \alpha(r_t)\,dt + \beta(r_t)\,dW_t^{\mathbb{P}}\) and \(dS_t = \mu_t S_t\,dt + \sigma_t S_t\,dW_t^{\mathbb{P}}\) driven by the same Brownian motion, the discounted price \(\tilde{S}_t = S_t / B_t\) where \(B_t = \exp(\int_0^t r_s\,ds)\) satisfies (by Itô's formula):
The market price of risk is
Note that \(\theta_t\) is now stochastic since both \(\mu_t\) and \(r_t\) may depend on the state. Under the measure change with \(W_t^{\mathbb{Q}} = W_t^{\mathbb{P}} + \int_0^t \theta_s\,ds\), the risk-neutral dynamics become \(d\tilde{S}_t = \sigma_t\tilde{S}_t\,dW_t^{\mathbb{Q}}\) and
The market is complete because there is exactly one source of randomness (one Brownian motion) and one traded risky asset (the stock). The single equation \(\mu_t - r_t = \sigma_t\theta_t\) uniquely determines \(\theta_t\), leaving no free parameters. This means there is a unique risk-neutral measure, and every contingent claim can be replicated by a dynamic portfolio of the stock and the bond.